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Week 9: Oscillations

9.1.2: The Simple Harmonic Oscillator Solution

As we formally derived above, the solution to the SHO equation of motion is;

x(t) = A cos(ωt + φ)

(801)

where A is called the amplitude of the oscillation and φ is called the phase of the oscillation. The amplitude tells you how big the oscillation is at peak (maximum displacement from equilibrium); the phase tells you when the oscillator was started relative to your clock (the one that reads t). The amplitude has to have the same units as the variable, as sin, cos, tan, exp functions (and their arguments) are all necessarily dimensionless in physics178. Note that we could have used sin(ωt+φ) as well, or any of several other forms, since cos(θ) = sin(θ + π/2). But you knew that179.

A and φ are two unknowns and have to be determined from the initial conditions, the givens of the problem, as noted above. They are basically constants of integration just like x0 and v0 for the one-dimensional constant acceleration problem. From this we can easily see that:

 

v(t) =

dx

= −ωA sin(ωt + φ)

(802)

 

 

 

dt

and

 

 

 

 

 

 

 

 

 

 

d2x

= −ω2A cos(ωt + φ) =

k

 

a(t) =

 

 

 

x(t)

(803)

 

dt2

m

This last result proves that x(t) solves the original di erential equation and is where we would have gotten directly if we’d assumed a general cosine or sine solution instead of an exponential solution at the beginning of the previous section.

Note Well!

An unfortunately commonly made mistake for SHO problems is for students to take Fx = ma = −kx, write it as:

k

 

a = m x

(804)

and then try to substitute this into the kinematic solutions for constant acceleration problems that we tried very hard not to blindly memorize back in weeks 1 and 2. That is, they try to write (for example):

 

1

 

 

1 k

 

x(t) =

 

at2 + v0t + x0

=

 

 

 

xt2 + v0t + x0

(805)

2

2

m

This solution is so very, very wrong, so wrong that it is deeply disturbing when students write it, as it means that they have completely failed to understand either the SHO or how to solve even the constant acceleration problem. Obviously it bears no resemblance to either the correct answer or the observed behavior of a mass on a spring, which is to oscillate, not speed up quadratically in time. The appearance of x on both sides of the equation means that it isn’t even a solution.

What it reveals is a student who has tried to learn physics by memorization, not by understanding, and hasn’t even succeeded in that. Very sad.

Please do not make this mistake!

Week 9: Oscillations

397

 

1.5

 

 

 

 

 

 

1

 

 

 

 

 

 

0.5

 

 

 

 

 

X

0

 

 

 

 

 

 

-0.5

 

 

 

 

 

 

-1

 

 

 

 

 

 

-1.5

 

 

 

 

 

 

0

1

2

3

4

5

 

 

 

 

T

 

 

 

8

 

 

 

 

 

 

6

 

 

 

 

 

 

4

 

 

 

 

 

 

2

 

 

 

 

 

V

0

 

 

 

 

 

 

-2

 

 

 

 

 

 

-4

 

 

 

 

 

 

-6

 

 

 

 

 

 

-8

 

 

 

 

 

 

0

1

2

3

4

5

 

 

 

 

T

 

 

 

60

 

 

 

 

 

 

40

 

 

 

 

 

 

20

 

 

 

 

 

A

0

 

 

 

 

 

 

 

 

 

 

 

 

-20

 

 

 

 

 

 

-40

 

 

 

 

 

 

-60

 

 

 

 

 

 

0

1

2

3

4

5

 

 

 

 

T

 

 

Figure 118: Solutions for a mass on a spring started at x(0) = A = 1, v(0) = 0 at time t = 0 (so that φ = 0). Note well the location of the period of oscillation, T = 1 on the time axis, one full cycle from the beginning.

9.1.3: Plotting the Solution: Relations Involving ω

Since we are going to quite a bit with harmonic oscillators from now on, we should take a few moments to plot x(t), v(t), and a(t).

We remarked above that omega had to have units of t1. The following are some True Facts involving ω that You Should Know:

ω =

 

2π

(806)

 

 

 

 

T

 

 

 

=

2πf

(807)

where T is the period of the oscillator the time required for it to return to an identical position and velocity) and f is called the frequency of the oscillator. Know these relations instantly. They are easy to figure out but will cost you valuable time on a quiz or exam if you don’t just take the time to completely embrace them now.

Note a very interesting thing. If we build a perfect simple harmonic oscillator, it oscillates at the same frequency independent of its amplitude. If we know the period and can count, we have just invented the clock. In fact, clocks are nearly always made out of various oscillators (why?); some of the earliest clocks were made using a pendulum as an oscillator and mechanical gears to count the oscillations, although now we use the much more precise oscillations of a bit of stressed crystalline quartz (for example) and electronic counters. The idea, however, remains the same.

178All function in physics that have a power series expansion have to be dimensionless because we do not know how to add a liter to a meter, so to speak, or more generally how to add powers of any dimensioned unit.

179I hope. If not, time to review the unit circle and all those trig identities from 11th grade...