Vychislitelny_praktikum
.pdf4. Найти систематическую составляющую методической погрешности сист β.
сист β |
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1 β5 |
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2 β5 |
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сист β |
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0.2 |
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0.00242 |
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0.00386 |
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0.1 |
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-0.00181 |
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-0.00609 |
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систβ |
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5 |
10 |
15 |
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-0.00095 |
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0.00819 |
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− 0.1 |
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0.00424 |
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-0.00862 |
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− 0.2 |
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-0.00573 |
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k |
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-0.00194 |
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0.02803 |
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-0.02819 |
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0.03174 |
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-0.08419 |
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0.13252 |
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-0.15401 |
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293
2. Построить зависимость δmin от параметра m при заданном параметре масштаба. |
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m1 := 0.. 18 |
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0.5 |
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0.4 |
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0.3 |
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δ(γ (m1) ,m1) |
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0.2 |
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0.1 |
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3.6 |
7.2 |
10.8 |
14.4 |
18 |
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m1 |
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3. Построить зависимость M[δm] от параметра m при заданном параметре γk. |
gk := |
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γ k := 0.005 |
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0.01 |
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0.02 if gk 3
0.05 if gk 4
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0.1 |
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Mδm(γ ,m) := 2 γ1 τ4 ∑ kγ+k 1 |
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k = 0 |
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0.5 |
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0.4 |
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δ(γ (m1) ,m1) |
0.3 |
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M δm(γ (m1) ,m1) |
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0.2 |
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0.1 |
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12 |
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18 |
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m1 |
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295
4. Построить зависимость M[δ] от параметра m при заданном параметре γk.
gk := |
γ k := 0.005 |
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gk |
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0.01 |
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0.02 if gk 3
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0.05 |
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0.1 |
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1 |
trunc(m) |
(β5(k ,γ ))2 |
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δ(γ ,m) := 1 − |
2 γ τ4 |
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k + 1 |
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k = 0 |
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trunc(m) |
γ |
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Mδm(γ ,m) := 2 γ1 τ4 |
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k +k 1 |
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k = 0 |
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Mδ(γ ,m) := δ(γ ,m) + Mδm(γ ,m) |
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0.5 |
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0.4 |
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δ(γ (m1) ,m1) |
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0.3 |
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M δm(γ (m1) ,m1) |
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M δ(γ (m1) ,m1) 0.2 |
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0.1 |
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0 |
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18 |
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m1 |
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5. Построить зависимость mopt от параметра |
γk. |
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Mδ(γ ,m2) := δ(γ ,m2) + Mδm(γ ,m2) |
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m2 := 12 |
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Given |
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Mδm(γ (m2) ,m2) |
δ(γ (m2) ,m2) |
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296
Find(m2) = 5.941 m3 := trunc(5.941) m3 = 5
0.005 |
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0.01 |
12 |
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TMopt := 0.02 |
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0.05 |
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0.1 |
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12 |
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TMopt 1 |
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6 |
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3 |
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0.02 |
0.04 |
0.06 |
0.08 |
0.1 |
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TMopt 0 |
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297