Vychislitelny_praktikum
.pdfm1 := 0.. 15 |
|
|
|
|
|
|
||
δ1V0m1 := δ1(χ ,m1,0) |
δ1V2m1 := δ1(χ ,m1,2) |
δ1V4m1 := δ1(χ ,m1,4) |
||||||
δ1V1m1 := δ1(χ ,m1,1) |
δ1V3m1 := δ1(χ ,m1,3) |
δ1V5m1 := δ1(χ ,m1,5) |
||||||
|
|
|
|
|
||||
δ1M 0 := δ1V0 |
δ1M 2 := δ1V2 |
δ1M 4 := δ1V4 |
||||||
δ1M 1 := δ1V1 |
δ1M 3 |
:= δ1V3 |
δ1M 5 |
:= δ1V5 |
||||
|
|
|
1 |
|
|
|
|
|
(δ1M 0 ) |
|
|
|
|
|
|
|
|
(δ1M |
1 )m10.833 |
|
|
|
|
|
||
|
|
m2 |
|
|
|
|
|
|
(δ1M |
2 ) |
0.667 |
|
|
|
|
|
|
|
|
m1 |
|
|
|
|
|
|
(δ1M |
3 ) |
|
0.5 |
|
|
|
|
|
|
|
m1 |
|
|
|
|
|
|
(δ1M |
4 ) |
m10.333 |
|
|
|
|
|
|
|
|
|
|
|
|
|
||
(δ1M |
5 ) |
m10.167 |
|
|
|
|
|
|
|
|
|
|
|
|
|
||
|
|
|
0 |
3 |
6 |
9 |
12 |
15 |
|
|
|
|
|
|
m1 |
|
|
3. Построить графические зависимости |
от параметра ; |
= 0 - 5 m = 2 - 6 |
||||||
Определить количество локальных экстремумов, значения параметра opt и |
||||||||
соотвествующие им значения погрешностей. |
|
|
i := 0.. 100 |
|
|
|
|
|
δ2V0i |
:= δ1(i 0.1 + 0.01,2,0) |
δ2V2i |
:= δ1(i 0.1 + 0.01,2,2) |
δ2V4i |
:= δ1(i 0.1 + 0.01,2,4) |
δ2V1i |
:= δ1(i 0.1 + 0.01,2,1) |
δ2V3i |
:= δ1(i 0.1 + 0.01,2,3) |
δ2V5i |
:= δ1(i 0.1 + 0.01,2,5) |
221
δ2M 0 := δ2V0 |
|
δ2M 2 := δ2V2 |
|
δ2M 4 := δ2V4 |
|||
δ2M 1 := δ2V1 |
|
δ2M 3 |
:= δ2V3 |
|
δ2M 5 := δ2V5 |
||
|
|
1 |
|
|
|
|
|
(δ2M 0 ) |
|
|
|
|
|
|
|
(δ2M |
1 )i0.833 |
|
|
|
|
|
|
|
i |
|
|
|
|
|
|
(δ2M |
2 )0.667 |
|
|
|
|
|
|
|
i |
|
|
|
|
|
|
(δ2M |
3 ) |
0.5 |
|
|
|
|
|
|
i |
|
|
|
|
|
|
(δ2M |
4 ) |
|
|
|
|
|
|
|
i0.333 |
|
|
|
|
|
|
(δ2M |
5 ) |
|
|
|
|
|
|
|
i0.167 |
|
|
|
|
|
|
|
|
0 |
2 |
4 |
6 |
8 |
10 |
|
|
|
|
|
i 0.1+0.01 |
|
|
δ3V0i := δ1(i 0.1 + 0.01,2,5) |
δ3V2i := δ1(i 0.1 + 0.01,4,5) |
|
δ3V4i := δ1(i 0.1 + 0.01,6,5) |
||||
δ3V1i := δ1(i 0.1 + 0.01,3,5) |
δ3V3i := δ1(i 0.1 + 0.01,5,5) |
|
|
||||
δ3M 0 := δ3V0 |
|
δ3M 2 := δ3V2 |
|
δ3M 4 := δ3V4 |
|||
δ3M 1 |
:= δ3V1 |
|
δ3M 3 := δ3V3 |
|
|
222