Kurs_vysshei_matematiki_UP_Berkov_N.A._2007-2
.pdfA = A1 · A2 · A3
P (A) = P (A1 · A2 · A3) = P (A1) · P (A2) · P (A3) = = (1 − 0, 1)(1 − 0, 2)(1 − 0, 5) = 0, 36
100 |
= 1 + 99 |
P (A) = |
C11 · C999 |
= |
1 · 99! · 10! · 90! |
= 0, 1 |
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10 |
= 1 + 9 |
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10 |
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9! · 90! · 100! |
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C100 |
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¯
A
5 |
= 3 |
+ 2 |
P (A¯) = |
C22 |
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1! · 2! · 3! |
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12 |
= 0, 1 |
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2 |
= 0 |
+ 2 |
C52 |
5! |
120 |
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¯ |
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− 0, 1 = 0, 9 |
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P (A) = 1 − P (A) = 1 |
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P (A) = PH1 (A) · P (H1) + PH2 (A) · P (H2),
A H1 H2
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P (H1) = |
3 |
P (H2) = 1 |
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¯ |
¯ |
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4 |
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4 |
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PH1 (A) = 1 − 0, 04 = 0, 96 |
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PH1 (A) = 0, 04 PH2 |
(A) = 0, 06 |
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PH2 (A) = 1 − 0, 06 = 0, 94 |
3 |
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1 |
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P (A) = 0, 96 · |
+ 0, 94 · |
≈ 0, 955. |
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4 |
4 |
n
Pi = 1
i=1
P2 : 0, 10 + P2 + 0, 25 + 0, 20 + 0, 30 = 1 P2 = 0, 15
M (ξ) = 0, 2 · 0, 1 + 0, 4 · 0, 15 + 0, 7 · 0, 25 + 0, 8 · 0, 20 + 1, 0 · 0, 30 = 0, 715
D(ξ) = 0, 22 · 0, 1 + 0, 42 · 0, 15 + 0, 72 · 0, 25+
+0, 82 · 0, 20 + 1, 02 · 0, 30 − 0, 7152 = 0, 067
σ(ξ) = D(ξ) ≈ 0, 259.
F (5) = 1 k · 5 = 1 k = 0, 2 |
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φ(x) = F (x) |
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φ(x) = |
0, |
x ≤ 0 |
, . |
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0, 2 |
0 < x ≤ 5 |
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F (x) ϕ(x)
F(x) |
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ϕ (x) |
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1 |
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0,2 |
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5 |
x |
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5 |
x |
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F (x) |
ϕ(x) |
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+∞ |
5 |
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M (ξ) = |
xφ(x)dx = |
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0, 2xdx = 0, 1x2 |
05 = 2, 5 |
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−∞ |
0 |
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+∞ |
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5 |
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D(ξ) = |
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x2φ(x)dx − 2, 52 = 0, 2x2dx − 2, 52 = |
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−∞ |
5 |
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0 |
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0, |
2x3 |
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= |
3 |
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0 − 2, 52 ≈ 2, 08σ(ξ) = D(ξ) ≈ 1, 44. |
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P {|ξ − 2| < ε} = 2 |
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ε |
2 |
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ε |
= 0, 67 |
(ε) = 0, 335. |
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σ |
1 |
(ε) ε ≈ 0, 97
A
A
M (ξ) D(ξ) σ(ξ) ξ
ξ
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0 |
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x ≤ 0, |
F (x) = |
k x |
0 < x 3, |
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0 |
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3 < x.≤ |
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k F (x) M (ξ) D(ξ) ϕ(x) F (x)
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ξ |
a = 1 σ = 3 |
P {|ξ − 1| < 2} |
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R |
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2 |
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R2 |
2 |
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M (ζ) = |
y |
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πR2− y |
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dy = 0. |
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−R |
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M (ξ · ζ) |
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√ |
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+∞ |
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+R |
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R2−x2 |
dy = |
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M (ξ · ζ) |
x · yϕ(xy) dxdy = πR2 |
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xdx |
2 2 |
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1 |
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−∞ |
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− |
R |
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√ |
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− R −x |
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+R |
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= |
x · 2√R2 − x2dx = 0 |
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πR2 |
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−R |
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μξζ = M (ξ · ζ) − M (ξ) · M (ζ) = 0 = |
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rξζ = |
μξζ |
= 0. |
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σξ σζ |
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rξζ = 0.
ξ ζ
rξζ = 0
|rξζ | 1
|rξζ | = 1 ζ = kξ + b ξ = kζ + b
μξζ |
= −1 rξζ 1. |
rξζ = σξ σζ |
ξ ζ
rξζ = 0
= ; =/ ; = ;
=/ .
(ξ; ζ)
ζ g(ξ)
M ζ −g(ξ) 2
g(ξ)
y = g(x) M ζ −g(ξ) 2
g(ξ)
ζ ξ
g(x) = kx + b ζ ξ
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ζ ξ |
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y = M (ξ) + rξζ |
σζ |
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x − M (ξ) . |
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σξ |
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g(x) = kx + b |
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M (ζ2 + k2 |
ξ2 |
+ b2 − 2kξζ − 2ζb + 2kbξ) = |
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Φ(k; b) = M ζ |
− g(ξ) |
2 = M (ζ − kξ |
− b)2 |
= |
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= M (ξ2) + k2M (ξ2) + b2 − 2kM (ξζ) − 2bM (ζ) + 2kbM (ξ). |
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∂k = 0 |
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k |
b |
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2kM (ξ2) − 2M (ξζ) + 2bM (ξ) = 0, |
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∂Φ |
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∂Φ |
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2b 2M (ζ) + 2kM (ξ) = 0; |
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− |
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∂b = 0 |
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b = M (ζ) |
− |
kM (ξ), |
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M (ξζ) |
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M (ξ)M (ζ) |
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k = |
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− |
2 |
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2 |
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(ξ) |
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M (ξ |
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− M |
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σ2 |
= M (ξ2) |
− |
M 2(ξ), |
M (ξζ) − M (ξ)M (ζ) |
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ξ |
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σξ σζ |
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k = rξζ |
σζ |
, b = M (ζ) − kM (ξ). |
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σξ |
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σζ |
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σζ |
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y = rξζ |
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+ M (ζ) − rξζ |
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· M (ξ). |
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σξ |
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σξ |
Φ(k; b) k b
k b
Φ(k; b)
σζ2(1 − rξζ2 ),
ζ g(ξ) = kξ + b
|rξζ | = 1 |
σζ2(1 − rξζ2 ) = 0 |
ζ |
g(ξ) |
rξζ = ±1 ζ = kξ + b |
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ζ = kξ + b |
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σζ2(1 − rξζ2 ) = 0 = rξζ2 = 1 = rξζ = ±1. |
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rξζ
ζ = g(ξ)
|rξζ |
|rξζ | |
ξ ζ |
ξ ζ |
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x = M (ξ) + rξζ |
σξ |
y − M (ζ) . |
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σζ |
M (ξ); M (ζ)
rξζ = ±1