Forms and methods of self-control:

Test tasks

1. The artificial feeding is feeding of children of the first 5-6 months of life by artificial milk formulas at presence of breast milk less than (in % from daily necessity):

   1. 40

   2. 35

   3. 30

   4. 25

   5. 20*

2. Advantages of sour formulas above sweet are all, except for:

   1. it promotes to the synthesis of vitamins (especially B-group)

   2. assist to normal development of flora

   3. activity of stomach and intestine is stimulated

3. digestion of protein is facilitated

4. it promotes formation of the colloid state of milk)*

3. Features of the high-adapted formulas, except for:

   1. Ratio of serum protein and casein – 60 : 40

   2. balanced maintenance of all vitamins

   3. the complete complex unsaturated fat acids is not contained*

   4. contains biologically active additions

   5. contains β-lactose

4. „Initial” formulas appoint to the children of age:

   1. 0-1 months

   2. 0-6 months*

   3. 0 – 12 months

   4. 4 – 12 months

   5. 6 – 12 months

5. 15 days child is on the artificial feeding. By what formula it is better to feed a child:

1. formula A (unadapted)

2. «Malish»

3. Formula B(unadapted)

4. «Hipp-1*»

5. Phenyl-free

6. Situation tasks

Task 1.

1 month child is on the artificial feeding. What formula is it better to feed a child by? What quantity of feeding on a day?

Answer: by the high-adapted formula, such as „Нірр- 1”, „Nutrilon-1”, „NAN -1”, and other 7 times per day in 3 hours.

Task 2.

1,5 months child with mass at birth 3500 g, is on the artificial feeding. What formula is it better to feed a child by? Define daily volume, volume on a 1 feeding.

Answer: Mass in 1,5 months: m = 3500 + 600 + 400 = 4500 g

Daily volume : V = 4500 : 5 = 900 ml

V on a 1 feeding = 900 : 7 = 145 ml.

Task 3.

3 month old child with mass at birth 3200 g, is on the artificial feeding by the adapted formula. Make one-day menu for a child. To define necessities in proteins, fats, carbohydrates, energy.

Answer: 1. mass in 3 months M = 3200+ 600+800+800 = 5400 g

2. Daily volume of feed is 1/6 from the mass V= 5400:6=900 ml

3. Volume on one feeding = 900 ml : 6 = 150 ml.

4. Necessity in proteins, fats, carbohydrates, kcal:

P= 2,5 g х 5,4 kg= 13,5 g. C = 12 g х 5,4 kg= 64,8 g.

F =6,5 g х 5,4 kg= 35,1 g. Kcal =120 kcal х 5,4 kg= 677,7 kcal.

5. Menu on 1 day:

6.00 formula „NAN” – 150 ml.

9.30 formula „NAN” – 150 ml.

13.00 formula „NAN” – 150 ml.

16.30 formula „NAN” – 150 ml.

20.00 formula „NAN” – 150 ml.

23.00 formula „NAN” – 150 ml.

Hardwares and material providing of training.

1. Tables:

“Classification of formulas for the artificial feeding”;

2. Set of test tasks for the entrance control (10 copies).

3. Set of situation tasks (10 copies).

4. Methodical developments.

Information sources:

Basic:

1). Т.Kapitan. Propedeutic of children’s diseases and nursing of the child. -Vinnitsa, 2006. – P.384-394

Additional:

1) Пропедевтика детских болезней . А.В. Мазурин, И.М. Воронцов. М.: Санкт-Петербург „Фолиант”. 2001. - С.874-884

Program of self-preparation of students to the theme:

1. To prepare tables on a theme „Artificial feeding”, in which proteins, fats, carbohydrates, energy composition of cow’s milk and basic most widespread formulas is represented

2. To make a few charts of the modern feeding of children, that is on the artificial feeding.