Вопрос № 42

Disposition of stright Ах+Ву+С=0, если А=0, С0:

parallel to axis ОХ;

axis ОХ;

parallel to axis ОУ;

axis ОУ;

passes through the origin coordinates;

Вопрос № 43

А(2; -3) and В(4;3). Coordinates of the point, divides the interval АВ in two:

(3;0).

(2; -3).

(4; 3).

(-2; 3).

(6; -3).

Вопрос № 44

Equalization of parabola, that symmetrical relative to the axis coordinates:

Вопрос № 45

Equalization of parabola, symmetrical relatively to axis of abscissas:

Вопрос № 46

Equalization of parabola directrix:

Вопрос № 47

Size of р parabola is calling:

Parameter.

Ordinate.

Abscissa.

Focus.

Directrix.

Вопрос № 48

Coordinates of focus F parabola:

и

Вопрос № 49

Coordinates of focus F parabola :

Вопрос № 50

Equalization of directrix parabola :

Вопрос № 51

Canonical equalization of hyperbola, where а=5, в=8:

Вопрос № 52

Canonical equalization of ellipse, if а=7, b=5:

Вопрос № 53

Canonical equalization, and distance between the focuses equal 8 and small axle b=3:

Вопрос № 54

Canonical equalization of ellipse, where large axle а=6 , concentricity. =0,5:

Вопрос № 55

What the dimension of matrix С=АВ, if А(m x k), В(k x n):

(m x n).

(k x n).

(n x m).

(m x k).

(n x n).

Вопрос № 56

What the dimension of matrix С=АВ, if А(2 x 3), В(3 x 4):

(2 x 4).

(2 x 3).

(2 x 2).

(3 x 4).

(4 x 3).

Вопрос № 57

What the dimension of matrix С=АВ, if А(3 x 4), В(4 x 1):

(3 x 1).

(3 x 4).

(4 x 4).

(3 x 3).

(1 x 3).

Вопрос № 58

What the dimension of matrix С=АВ, if А(2 x 4), В(4 x 2):

(2 x 2).

(4 x 2).

(2 x 8).

(2 x 4).

(4 x 4).

Вопрос № 59

Find an element С₂₃ matrix С=АВ, if , :

10.

5.

-10.

-5.

-9.

Вопрос № 60

Find an element С₁₂ matrix С=АВ, if , :

-5.

5 .

10.

-10.

-9.

Вопрос № 61

Find an element С₃₃ matrix С=АВ, if, :

2.

-5.

-10.

10.

5.

Вопрос № 62

If the determiner square matrix equals zero, she called:

Singular.

Nonsingular.

Unit.

Inverse.

Diagonal.

Вопрос № 63

If the determiner if square matrix is not equal zero, she called:

Singular.

Nonsingular.

Unit.

Inverse.

Diagonal.

Вопрос № 64

The system of linear equalizations is calling compatible, if:

it has only one solution.

it has at least one solution.

It doesn’t have a solution.

The solutions consist from the whole numbers.

The solutions only positive numbers.

Вопрос № 65

n – unknown quantity, m – quantity of the equalization of the system. What kind of condition contribute application the Kramer’s rule?

m = n.

m  n.

m  n .

m < n.

m > n.

Вопрос № 66

Coordinates of focus F parabola :

Вопрос № 67

If the equalization’ system doesn’t have solution, then the system is calling:

Incompatible .

Compatible.

Determinate.

Heterogeneous.

Homogeneous.

Вопрос № 68

If in the Kramer’s method =0, _х0, then a system:

Incompatible .

Compatible.

Determinate.

Heterogeneous.

Homogeneous.

Вопрос № 69

How is located the straight Ах+Ву+С=0, if В=0, С0:

Parallel to axis ОУ.

Axis ОХ.

Parallel to axis ОХ.

Axis ОУ.

Passes through the origin coordinates.

Вопрос № 70

Formula of the calculus of the distance from point М(х₁,у₁) to the straight Ах+Ву+С=0:

Вопрос № 71

In what meanings а and в these straights ах-2у-1=0, 6х-4у-в=0 are parallel:

а=3, в2.

а=2, в=2.

а=3, в=2.

а= -3, в2.

а=6, в6.

Вопрос № 72

In what meanings а and в these straights у = ах+2, у = 5х - в are parallel:

а= 5, в-2.

а= -1/5, в-2.

а= -1/5, в= -2.

а= -5, в= -2.

а5, в= -2.