P.K.Townsend - Black Holes
.pdfChapter 6
Black Hole Mechanics
6.1Geodesic Congruences
De nition A congruence is a family of curves such that precisely one curve of the family passes through each point. It is a geodesic congruence if the curves are geodesics.
The equations of a geodesic congruence may be written as x = x (y ; ) where the parameters y ; = 0; 1; 2 label the geodesic and is an a ne parameter on the geodesic, i.e.
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(6.1) |
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is the tangent to the geodesics such that t Dt = 0. |
Since the parameter |
is a ne, t2 1 for timelike geodesics (while t2 0 for null geodesics). The vectors
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(6.2) |
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may be considered as a basis of `displacement' vectors across the congruence:
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. neighboring geodesics |
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. ....... .......... |
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Note that t and commute (since we could choose coordinates x s.t. t = @=@ and = @=@y ), so
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t @ @ t |
(6.3) |
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t (@ + ) (@ t + t ) |
(6.4) |
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t D D t (by symmetry of connection) |
(6.5) |
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or |
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t D = B |
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(6.6) |
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B = D t |
(6.7) |
measures the failure of the displacement vectors to be paralelly-transported along the geodesics, i.e. it measures geodesic deviation.
A geodesic nearby some ducial geodesic may now be speci ed by a displacement vector , but this speci cation is not unique because 0 = +at (a = constant) is a displacement vector to the same geodesic.
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ducial |
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gedoesic |
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+ at
neighbouring geodesic
For timelike geodesics we can remove this ambiguity by requiring to be orthogonal to t, i.e.
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(6.8) |
Strictly, speaking we can only make such a choice at a given value of , by choosing the origin of across the congruence. However
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(t D ) t (since t Dt = 0) |
(6.9) |
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B t = ( D t ) t |
(6.10) |
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(6.11) |
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since t2 1 for timelike congruences, so if t is chosen to vanish at one value of it will do so for all .
For null congruences the condition t = 0 is not su cient to eliminate
the ambiguity in the choice of because |
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0 t = |
( + at) t = t + at t |
(6.12) |
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(6.13) |
when t2 = 0, which means that 0 t = 0 whenever t = 0. The problem is that the 3-dim space of vectors orthogonal to t now includes t itself, so the displacement vectors orthogonal to t specify only a two-parameter family of geodesics. Displacement vectors to the other null geodesics in the congruence have a component in the direction of a vector n that is not
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orthogonal to t. The choice of n is otherwise arbitrary (it is analogous to the choice of gauge in electrodynamics), but it is convenient to choose it such that
n2 = 0; n t = 1 |
(6.14) |
e.g. if t is tangent to an outgoing radial null geodesic, then n is tangent to an ingoing one.
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......outgoing radial |
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null geodesic |
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t = p |
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Consistency of the choice of n requires that n2 and n t be independent of, which is satis ed if
t Dn = 0 |
(6.15) |
i.e. we choose n to be parallely-transported along the geodesics.
Having made a choice of the vector n, we may now uniquely specify a twoparameter subset of geodesics of a null geodesic congruence by displacement vectors orthogonal to t by requiring them to also satisfy
n = 0 |
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(6.16) |
The vectors now span a two-dimensional subspace, T?, of the tangent space, that is orthogonal to both t and n, i.e. P = , where
P = + n t + t n |
(6.17) |
projects onto T?.
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Proposition |
P = ) t D |
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, where |
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(6.18) |
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i.e. if 2 T? initially, it remains in this subspace. |
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Proof |
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t D |
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(if P = ) |
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(6.20) |
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(6.21) |
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(6.22) |
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(6.23) |
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B is e ectively a 2 2 matrix. We now decompose it into its algebraically |
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irreducible parts |
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(6.24) |
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where |
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expansion |
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shear |
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B( ) |
2 P B |
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Notation: |
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Lemma |
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t[ B ] = t[ B ] |
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Proof |
Using t Dt = 0 and t2 = 0, we have |
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B^ = B + t n B + n B n t + B n |
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(6.25) |
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Hence result. ([ |
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Proposition |
The tangents t are normal to a family of null hypersurfaces i !^ = 0. |
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Proof |
If !^ = 0, then |
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(6.26) |
t[ !^ ] t[ B ] |
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t[ B ] (by Lemma) |
(6.27) |
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(6.28) |
so t is normal to a family of hypersurfaces by Frobenius' theorem. (In this case we can take t = l).
Conversely, if t is normal to a family of null hypersurfaces, then Frobenius' theorem implies t[ D t ] = 0. Then, reversing the previous steps we
nd that, |
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0 = t[ !^ ] = |
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(6.29) |
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Contract with n. Since n t = 1 and n!^ = !n^ |
= 0 (because !^ contains |
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the projection operator P ), we deduce that !^ = 0. |
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If !^ = 0 we have a family of null hypersurfaces. The family is parameterized by the displacement along n
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family of
null hypersurfaces
6.1.1Expansion and Shear
Two linearly independent vectors (1) and (2) orthogonal to n and t determine an area element of T?. The shear ^ determines the change of shape of this area element as increases. The magnitude of the area element de ned by (1) and (2) is
a = " t (1) (2) |
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(6.30) |
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Since t Dt = 0 and t Dn = 0, we have |
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(6.31) |
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(6.32) |
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(6.34) |
i.e. measures the rate of increase of the magnitude of the area element. If> 0 neighboring geodesics are diverging, if < 0 they are converging.
Raychaudhuri's equation for null geodesic congruences
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(6.35) |
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(6.39) |
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= P B P B + P B t n B + P B n t B t t R |
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(6.41) |
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This is Raychaudhuri's equation for null geodesic congruences.
Some consequences of Raychaudhuri's equation for null hypersurfaces
Proposition The expansion of the null geodesic generator of a null hypersurface, N, obeys the di erential inequality
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(6.43) |
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provided the spacetime metric solves Einstein's equations G = 8 GT and T satis es the weak energy condition.
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Proof ^2 0 because the metric in the orthogonal subspace T? (to l and n) is positive de nite. !^2 0 also, but this comes in with wrong sign, however !^ = 0 for a hypersurface. Thus Raychaudhuri's equation implies
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(6.45) |
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(6.46) |
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Corollary If = 0 < 0 at some point p on a null generator of a null hypersurface, then ! 1 along within an a ne length 2= j 0j.
Proof Let be the a ne parameter, with = 0 at p. Now
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where, since = 0 at = 0, the constant cannot exceed 0 1. Thus |
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If 0 < 0 the right-hand-side ! 1 when = 2= j 0j, so ! 1 within that a ne length.
Interpretation When < 0 neighboring geodesics are converging. The attractive nature of gravitation (weak energy condition) then implies that they must continue to converge to a focus or a caustic.
Proposition |
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If N is a Killing horizon then B = 0 and |
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(6.49) |
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Proof Let be the Killing vector s.t. = fl (l Dl = 0) on N for some non-zero function f. Then
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(since !^ = 0 for family of hypersurface) |
(6.50) |
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B( )P P D( l )P |
(6.51) |
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(6.52) |
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(since P = P = 0) |
(6.53) |
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In particular = 0, everywhere on N, so d =d = 0. |
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Corollary For Killing horizon N of |
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R jN = 0 |
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(6.54) |
^
Proof Using d =d = 0 and B = 0 in Raychaudhuri's equation.
6.2The Laws of Black Hole Mechanics
Previously we showed that 2 is constant on a bifurcate Killing horizon. The proof fails if we have only part of a Killing horizon, without the bifurcation 2-sphere, as happens in gravitational collapse. In this case we need the:
6.2.1Zeroth law
obeys the dominant energy condition then the surface gravity is constant on the future event horizon.
Proof Let be the Killing vector normal to H+ (here we use the theorem that H+ is a Killing horizon). Then since R = 0 and 2 = 0 on H+, Einstein's equations imply
0 = T jH+ J jH+ |
(6.55) |
i.e. J = ( T ) @ is tangent to H+ . It follows that J can be expanded on a basis of tangent vectors to H+
J = a + b1 (1) + b2 (2) on H+ |
(6.56) |
But since (i) = 0 this is spacelike or null (when b1 = b2 = 0), whereas it must be timelike or null by the dominant energy condition. Thus, dominant
energy ) J / and hence that |
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(6.57) |
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(6.58) |
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(6.59) |
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(6.60) |
109
)@ / ) t @ = 0 for any tangent vector t to H+
) is constant on H+.
6.2.2Smarr's Formula
Let be a spacelike hypersurface in a stationary exterior black hole spacetime with an inner boundary, H, on the future event horizon and another boundary at i0.
........... H
................ .
..................
.... ..... .......
. .. .. ..
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... .. . ..
...... ... ...
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...... . .
.. .
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H |
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. .. i0
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The surface H is a 2-sphere that can be considered as the `boundary' of the black hole.
Applying Gauss' law to the Komar integral for J we have |
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J = |
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Z dS D D m + |
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IH dS D m |
(6.61) |
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8 G |
16 G |
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by Killing vector Lemma |
(6.62) |
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where JH is the integral over H. Using Einstein's equation, |
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(6.63) |
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In the absence of matter other than an electromagnetic eld, we have T = T (F ), the stress tensor of the electromagnetic eld. Since g T (F ) = T (F ) = 0 we have
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J = Z dS T (F )m + JH |
(6.64) |
for an isolated black hole (i.e. T = T (F )).
110