ВМ 4 ИДЗ 1- 5 2009
.docВМ 4 ИДЗ 5 - 2009 Найти наибольшее и наименьшее значения функции f(x, y) в области D
Вар - т |
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f(x, y) |
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D |
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1 |
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2x2 + xy + 2y2 - 3x - 2y + 1 |
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x ≥ 0; y ≥ 0; 2x + 3y ≤ 6 |
2 |
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3x2 + xy + y2 - 2x - 3y + 2 |
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x ≥ 0; y ≥ 0; 2x + 5y ≤ 10 |
3 |
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3x2 + 3xy + 2y2 + 7x + 6y - 2 |
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x ≤ 0; y ≤ 0; 2x + 3y ≥ -6 |
4 |
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2x2 + 4xy + y2 + 8x + 12y + 4 |
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x ≤ 0; y ≤ 0; 2x + 5y ≥ -10 |
5 |
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2x2 + 2xy + 4y2 - 6x - 8y - 3 |
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x ≥ 0; y ≥ 0; 3x + 4y ≤ 12 |
6 |
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-8x2 - 4xy - y2 - 8x + 12y + 1 |
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x ≥ 0; y ≤ 0; 2x - 3y ≤ 6 |
7 |
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2x2 + 3xy + 3y2 + 5x + 10y - 1 |
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x ≤ 0; y ≤ 0; x + y ≥ -12 |
8 |
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3x2 + 4xy + 4y2 - 12x - 16y + 4 |
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x ≥ 0; y ≥ 0; x + 3y ≤ 6 |
9 |
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3x2 + 6xy + 2y2 - 8x - 4y + 2 |
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x ≤ 2; y ≤ 3; 3x + 2y ≥ 6 |
10 |
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x2 + 2xy - 3y2 - 10x + 6y + 4 |
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x ≤ 3; y ≤ 5; 5x + 3y ≥ 15 |
11 |
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x2 + 3xy + 4y2 + 5x - 3y - 3 |
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x ≥ -8; y ≤ 2; x - 4y ≤ -8 |
12 |
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2x2 + 2xy - 4y2 - 2x - 10y + 4 |
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x ≥ 0; y ≤ 0; x - y ≤ 3 |
13 |
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3x2 + 6xy - 2y2 - 10y + 4 |
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x ≥ 0; y ≤ 0; x - 2y ≤ 4 |
14 |
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-3x2 + 6xy - 2y2 - 3x - 5y + 2 |
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x ≤ 5; y ≤ 5; x + y ≥ 5 |
15 |
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-4x2 + 3xy - 2y2 - 3x + y |
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x ≤ 0; y ≤ 0; x + y ≥ -3 |
16 |
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2x2 - 2xy - 4y2 - 6x - 4y + 3 |
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x ≥ 0; y ≤ 0; 3x - 4y ≤ 12 |
17 |
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-3x2 - 3xy - 2y2 - x - 3y + 1 |
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x ≥ 0; y ≤ 0; x - 2y ≤ 4 |
18 |
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3x2 - 6xy + 2y2 - 2x - 4y + 1 |
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x ≤ 4; y ≥ -4; x - y ≥ 4 |
19 |
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-8x2 - 4xy - y2 - 4x + 2y + 3 |
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x ≤ 0; y ≥ 0; 4x - 3y ≥ -24 |
20 |
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4x2 - 2xy + 4y2 + 4x + 14y + 1 |
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x ≤ 0; y ≤ 0; x + y ≥ -6 |
21 |
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-3x2 - 4xy - 4y2 + 2x - 4y |
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x ≥ 0; y ≥ 0; 3x + 5y ≤ 15 |
22 |
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4x2 - 6xy + 4y2 - 4x - 4y + 3 |
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x ≤ 3; y ≤ 3; x + y ≥ 3 |
23 |
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3x2 - 4xy + 4y2 + 2x - 4y + 3 |
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x ≤ 0; y ≥ 0; 2x - y ≥ -4 |
24 |
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3x2 - 8xy + 5y2 - 2x + 4y + 2 |
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x ≤ 6; y ≤ 3; x + 2y ≥ 6 |
25 |
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2x2 + 5xy + 3y2 - 2x - 2y + 5 |
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x ≥ -3; y ≤ 4; 4x - 3y ≤ -12 |
26 |
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4x2 + 6xy + 4y2 + 10x - 3y + 3 |
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x ≥ -4; y ≤ 2; x - 2y ≤ -4 |
27 |
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x2 + 6xy + 6y2 - 8x - 12y + 1 |
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x ≤ 6; y ≤ 3; x + 2y ≥ 6 |
28 |
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2x2 - 3xy + 2y2 - 4x - 4y + 9 |
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x ≤ 6; y ≤ 0; x + y ≥ 6 |
29 |
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3x2 + 3xy + 2y2 + 15x + 20y - 60 |
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x ≤ 0; y ≤ 0; 3x + 2y ≥ -72 |
30 |
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3x2 - 6xy + 2y2 - x - 2y + 1 |
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x ≤ 2; y ≥ -2; x - y ≥ 2 |
ВМ 4 ИДЗ 3a (Фaкультативно) Найти максимальную крутизну поверхности z = f(x,y) в точке хo; уo .
Вар - т |
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f(x,y) |
xo |
yo |
tgφ |
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1 |
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x*exp(6x2 + 5x + y - 4y2) |
1 |
2 |
3*e -3 √61 ~ 1,167 |
2 |
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ln(2x2 + 4xy + y2) |
3 |
2 |
(2 / 23)* √41 ~ 0,557 |
3 |
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arctg[(2x + 3) / (1 + 4y)] |
-1 |
1 |
(1 / 13)* √29 ~ 0,414 |
4 |
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xy + ln(x3 + 6xy - 2y2) |
2 |
1 |
(2 / 9)* √202 ~ 3,16 |
5 |
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arcsin[(x + y) / (2x + 3y)] |
7 |
-3 |
(1 / 15)* √58 ~ 0,508 |
6 |
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(x + y)*exp(x2 + 2xy - y2) |
1 |
3 |
~ 4,9 |
7 |
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ln[(x3y + 3xy2 + y2) / x] |
2 |
1 |
~ 1,6 |
8 |
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arcsin[(2x + y) / (x + 3y)] |
-1 |
-2 |
~ 0,28 |
9 |
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arctg[(x – y2) / (x + y2)] |
3 |
2 |
(4 / 25)* √10 ~ 0,506 |
10 |
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(2x - 3y)*exp(8x2 - 4xy + 2x + 1) |
1 |
2 |
e -2* √173 ~ 1,78 |
11 |
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ln[(x2 + xy + y) / (2x + y2)] |
2 |
-1 |
0,2* √458 ~ 4,28 |
12 |
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arccos[(3x - y) / (4x + y)] |
2 |
2 |
(1 / 30)* √42 ~ 0,216 |
13 |
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(y - 2x)*exp(2x2 + 4xy - y - y2) |
1 |
4 |
6*e -2 √61 ~ 5,285 |
14 |
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ln[(x2 – x - y + 2y2) / (x + y)] |
3 |
1 |
~ 0,5 |
15 |
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arctg[(2x + 3y) / (3x - 2y)] |
2 |
-1 |
0,2* √5 ~ 0,447 |
16 |
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√[(x2 + xy) / (y2 + xy)] |
3 |
2 |
(1 / 24)* √78 ~ 0,368 |
17 |
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(x - y)*exp(3x2 - 6xy - x + y2) |
2 |
1 |
e -1 √157 ~ 4,61 |
18 |
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arccos[(4x + 3y) / (3x - y)] |
2 |
-1 |
(13 / 84)* √30 ~ 0,848 |
19 |
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√[(3x2 - y2) / (3xy + 2y2)] |
1 |
1 |
~ 1 |
20 |
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ln[(x + 3y) / (4x2 + 2xy + 3y2) |
3 |
1 |
(1 / 90)* √1810 ~ 0,473 |
21 |
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arctg[(2xy - y) / (x2 + y2)] |
3 |
4 |
(1 / 205)* √305 ~ 0,085 |
22 |
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(3x - y)*exp(-x2 + 3xy + 2y + 3x + 2y2 - 1) |
-1 |
1 |
e -4 √1010 ~ 0,582 |
23 |
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√[(4x2 + 2xy) / (3xy - 2y2)] |
2 |
1 |
3 / 8 = 0,375 |
24 |
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ln[(6x2 + 2xy - 3y2 - 5)/(4x2 – 2xy + y – 1)] |
3 |
-1 |
0,025* √353 ~ 0,47 |
25 |
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arctg[(3x2 - y2) / (2x + 3y)] |
2 |
-2 |
(2 / 17)* √41 ~ 0,753 |
26 |
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arctg[(4x - y) / (2x + 3y)] |
1 |
-2 |
(7 / 26)* √5 ~ 0,602 |
27 |
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(x – 2y)*exp(-2x2 + 2xy - y + x) |
1 |
- 1 |
e -2 √197 ~ 1,9 |