Построение таблицы значений функции
>> x=[0.3 0.6 0.9 1.4 1.8 2.6];
>> y=sin(x).^2./(1+cos(x)+exp(-x).*log(x));
>> y=sin(x)^2./(1+cos(x)+exp(-x).*log(x));
??? Error using ==> mpower
Matrix must be square.
>> x
x =
0.3000 0.6000 0.9000 1.4000 1.8000 2.6000
>> y
y =
0.0821 0.2064 0.3887 0.7751 1.0901 1.2413
>> x=[1, 1.3, 1.5, 1.6, 1.9, 2.1]
x =
1.0000 1.3000 1.5000 1.6000 1.9000 2.1000
>> x=[1:-0.2:-2]
x =
Columns 1 through 8
1.0000 0.8000 0.6000 0.4000 0.2000 0 -0.2000 -0.4000
Columns 9 through 16
-0.6000 -0.8000 -1.0000 -1.2000 -1.4000 -1.6000 -1.8000 -2.0000
>> x=[1:0.2:2]
x =
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
>> x=(0:0.1:00.5)'
x =
0
0.1000
0.2000
0.3000
0.4000
0.5000
>> x=1:5
x =
1 2 3 4 5
>> x=0:0.05:1;
>> y=exp(-x).*sin(10*x);
>> x
x =
Columns 1 through 8
0 0.0500 0.1000 0.1500 0.2000 0.2500 0.3000 0.3500
Columns 9 through 16
0.4000 0.4500 0.5000 0.5500 0.6000 0.6500 0.7000 0.7500
Columns 17 through 21
0.8000 0.8500 0.9000 0.9500 1.0000
>> y
y =
Columns 1 through 8
0 0.4560 0.7614 0.8586 0.7445 0.4661 0.1045 -0.2472
Columns 9 through 16
-0.5073 -0.6233 -0.5816 -0.4071 -0.1533 0.1123 0.3262 0.4431
Columns 17 through 21
0.4445 0.3413 0.1676 -0.0291 -0.2001
>> [x' y']
ans =
0 0
0.0500 0.4560
0.1000 0.7614
0.1500 0.8586
0.2000 0.7445
0.2500 0.4661
0.3000 0.1045
0.3500 -0.2472
0.4000 -0.5073
0.4500 -0.6233
0.5000 -0.5816
0.5500 -0.4071
0.6000 -0.1533
0.6500 0.1123
0.7000 0.3262
0.7500 0.4431
0.8000 0.4445
0.8500 0.3413
0.9000 0.1676
0.9500 -0.0291
1.0000 -0.2001
Построение графиков функции одной переменной
>> x=0:0.5:1;
>> y=exp(-x).*sin(10*x);
>> plot(x,y)
>> x=0:0.1:1;
>> y=exp(-x).*sin(10*x);
>> plot(x,y)
>> x=-1:0.5:-0.3;
>> f=sin(x.*-2);
>> g=(1.4*x.^-3);
>> plot(x,f,x,g)
>> plot(x,f,'k-',x,g, 'k:')
Умножение векторов
>> a=[1.3; -4.3; 0.9];
>> b=[4.3; 6.7; -2.9];
>> s=sum(a.*b)
s =
-25.8300
>> s=dot(a,b)
s =
-25.8300
>> d=sqrt(dot(a,a))
d =
4.5815
>> a=[1.2; -3.7; 0.9];
>> b=[4.2; 6.1; -2.5];
>> c=cross(a,b)
c =
3.7600
6.7800
22.8600
>> cross(a,b)+cross(b,a)
ans =
0
0
0
>> a=[3.6; 0; 0];
>> b=[0.3; 2.5; 0];
>> c=[-0.3; -1.2; 2.6];
>> v=abs(dot(a, cross(b,c)))
v =
23.4000
>> a=[1; 2; 3];
>> b=[5; 6; 7];
>> c=a*b'
c =
5 6 7
10 12 14
15 18 21
Двумерные масивы часть 1/2
>> a=[3 1 -1; 2 4 3];
>> b=[4 3 -1
2 7 0
-5 1 2]
b =
4 3 -1
2 7 0
-5 1 2
>> c=[[3; 4] [-1; 2] [7; 0]]
c =
3 -1 7
4 2 0
>> whos
Name Size Bytes Class Attributes
a 2x3 48 double
ans 1x1 8 double
b 3x3 72 double
b1 2x2 32 double
b2 3x3 72 double
c 2x3 48 double
d 2x1 16 double
f 2x1 16 double
i1 3x1 24 double
ind 3x3 9 logical
ind1 3x3 72 double
ind2 3x3 9 logical
j1 3x1 24 double
k 1x1 8 double
km 1x3 24 double
m 1x1 8 double
n 1x2 16 double
p 2x3 48 double
r 2x3 48 double
s 2x3 48 double
x 1x8 64 double
xm 1x3 24 double
>> c(2,3)
ans =
0
>> c(1,1) +c(2,2)+c(2,3)
ans =
5
>> n=[1 2];
>> m=[2 3];
>> b1=b(n, m)
b1 =
3 -1
7 0
>> c(5)
ans =
7
>> ind=b<0
ind =
0 0 1
0 0 0
1 0 0
>> f=b(ind)
f =
-5
-1
>> f=b(b<0)
f =
-5
-1
>> ind1=[0 0 1; 0 0 0; 1; 0 0];
??? Error using ==> vertcat
CAT arguments dimensions are not consistent.
>> ind1=[0 0 1; 0 0 0; 1 0 0];
>> b(ind1)
??? Subscript indices must either be real positive integers or logicals.
>> ind2=logical(ind1);
>> x=[1 2 5 3 4 5 1 5];
>> [m, k]=max(x)
m =
5
k =
3
>> xm=x(x==5)
xm =
5 5 5
>> km=find(x==5)
km =
3 6 8
>> [i1, j1]=find(b<=0)
i1 =
3
1
2
j1 =
1
3
3
>> k=find(b<=0)
k =
3
7
8