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within region n.

4.2 Reynolds' Transport Theorem

139

:_\~;(;:·:.. ·

:::/ID the following the arguments of the tensor quantities are dropped in order to simplify i::i(/tbe notation. However, in cases where additional information is needed, they will be ::'{iemployed. Hence, relation (4.25):1 reads as

~t./ <I>dv =

/ (<ii+ <I>divv)clv ,

(4.26)

n

n

 

·.:._:·.·_.·:: ·..

 

 

;:':!}~herewe have assumed smoothness of the spatial velocity field v.

 

Other forms of the time rate of change of the integral (4.22) result from

(4.26)

.:' 'by means of the material time derivative of the spatial scalar field <P

in the fonn of

::i;::·_>_eq. {2.25), and the product rule (l .287), i.e.

 

 

 

E_ <I>dv = f(O<I> + grad<P · v + <I>divv)dv

 

Dt. .

.

8t:

 

 

 

n

n

 

D<I>

 

 

 

.

 

 

 

 

= ./ (div(<I>v) +

{)t

)dv ,

(4.27)

 

 

 

n

 

 

 

 

/~ndfinally, using the divergence theorem according to (l.297),

 

-D /" <I>clv = I<I>v ·nds + -D<I~.-dv .

(4.28)

.Dt.

.

 

'

{)t

 

n

an

n

 

 

.·.·..

 

 

 

 

 

:'./.·.::· TI.ie first term on the right-hand side

of eq. (4.28) characterizes the rate of transport

\(Or the outward normal flux)

of <I>v across the surface on out of region n, which is

(:(_::_assumed to be fixed. This contribution arises from the moving region. The second }):.·_term denotes the local time rate of change of the spatial scalar field cJ>

:/:··:·In (4.28) n denotes the outward unit normal .field acting along DH. Relation {4.28) is

:\:·_.·referred to as Reynolds' transport theorem.

Another very useful relationship is obtained by considering the scalar-valued func ..

.·tion

l(t) = ./ p(x, t)W(x, t)dv ,

(4.29)

 

n

 

 

 

:;__.. which is deduced from eq. (4.22) by changing <I> into fJ°W, where \JI

denotes a smooth

... ·spatial scalar field describing some physical quantity of a particle

in space per unit

:_.:··mass at time t.

 

 

 

 

W·ith reference to eq. (4.26) the time rate of c·hange off(t) is .then given as

D ;·

p'lldv =

;· - ·

(4.30)

-

.

(p\JI + p\Jldivv)dv .

 

Dt .

 

 

 

n

 

n

 

 

140 4 ·Balance Princip-Jes

We now apply the product rule of differentiation and the rate form (~.12) of continuity mass equation to the first term of the integrand in (4.30). We find p\J! = pW + p\JJ =

p\J! - p\J! divv. As a consequence of the continuity mass equation, we obtain

 

gt/p(x, t)W(x, t)dv =/ p{x, t)~(x,t)dv .

(4.31)

n

n

 

Assume \JI = 1 so that the volume integral i(t) .in (4.29) represents.mass within region n (see eq. (4.7)). For that cas-e, eq. (4..31) reduces to (4.B"h~ since \lf = 0.

EXAMPLE 4.2 Show that the important relation (4.31) may also be obtained.by changing the scalar-valued integral (4.29) over space into an integral over mass.

Solution.

Using the infinitesimal mass element drn = pdv (see eq. (4.5h) we find

that

 

D ( Dt .

n

\JI

(

)(

(

.

J~ Dw{x, t)

(

(

) . (

)

dv , (4.32)

x, t

 

p x, t)dv) =.

Dt

dm =.

p x, t

\JI x, t

 

 

 

 

 

 

n

 

n

 

 

 

 

since the .infinitesimal mass element is not affected by the material time derivative. II

.,.,,,.,_.•• ,,.,,,.,,_,..,.,,,,_,,,.• ,,..,....,.,_,_,,,.,.,.~.-·-·-'':'·'."'''"'':'·,,, ___.,_,,,.,,.,,.,,...,______,.,,,,:...._,____,,_,,,,,._,,___·-:''~··,.,-::·-,-..,--.•,,,.,,.,:,.,:-··-...·--·-''''•'"':''".."'"--.·---,·'''''·'''",,.,,.•,-.::•·'·'"."''-''·'-·-···'·"'''·''''··•.•,.,,,,,,,,.,,,•.,, .·:,1,

EXERCISES

1.Derive the rate form of continuity ·mass equation (4. 12) in the spatia·1 description, i.e. /j + pdivv = 0, by applying relation (4.26) and using eq. (4.8)2.

2.Essentially the same statements as derived in eqs. (4.26), (4.27.h, (4.28) and (4.31) result for the material time derivative of a vector-valued volume integral

(or tensor-valued volume -integral) by regarding either <I> or \JI as a smooth (continuously differentiable) spatial vector field u = u(x_, t).

Show that

gt/ud·v = /(u+udivv)d'V= /[~~ +div(u®v)]clv

n

n

 

n

 

 

 

= .!u(v · n)ds + /

~;dv

,

(4.33)

 

an

n

 

 

 

 

Dt ./' pudv =

.plid-v

,

(4.34)

 

 

n

n

 

 

where the material time derivative of u is ti =au/at+ {gradu}v. The vector v denotes the spatial velocity.

4.3 Momentum Balance PrinCiples

141

4.3 Momentum Balance Principles

In this section we -describe balance of .linear and angular momentum for a closed and an open system, essential in .continuum mechanics. These principles are valid for the whole or arbitrary parts of a continuum body B. In addition, we de.rive Cauchy's first equation of motion and show the symmetry of the Cauchy stress tensor.

Balance of linear and .angular momentum in spatial and material description.

Consider a continuum body B with a set of particles occupying an arbitrary region n with boundary surface an at time t.

We consider a closed system with a given motion x = x{X, t), spatial mass density p = p(x, t) and spatial velocity field v ·= v(x, t). We define the total linear ·momentum L (or in the .literature .sometimes called translational momentum) by the vector-valued function

L(t) = ./ p(x, t)v(x, t)dv = ./ Pn(X)V(X, t)dV ,

(4.35)

fl

Ou

 

and the total angular momentum J relative to a fixed point (characterized by the position vector x0) as

J(t) = ./ r x p(x, t)v(x, t)dv = / r x p0 (X)V{X, t)dF .

(4.36)

n

no

 

We used the identity (2.8), conservation of mass in the form of pdv = p0cfl/ and the definition of the position vector r, i.e.

r(x) = X - Xo = x(X_,:t) - Xo .

(4.37)

Jn the literature the angular ·momentum J is often .referred to as the moment of mo- mentum or the rotational momentum.

Momentun1 equations (4.35) and (4.36) are formulated with respect to the current and reference configurations with associated quantities p, v, dv and p0 , V, dl/, respectively. Linear momentum and angular momentum per unit current and reference volume are defined as the products pv, {Jo V and r x pv_, r x p0 V, respectively. To avoid congestion we often omit the arguments of the tensors for much of the remainder of this section.

The material time derivatives of linear and angular momentum (4.35h and (4.36h -of the particles which fill an arbitrary region n result in fundamental axioms called momentum balance principles for a continuum body. We postulate the balance of linear momentum as

.

Dr

D ;·

,

(4.38)

L(t) = Dt.

pvdv = Dt.

PnVcW = F(t)

 

 

n

no

 

 

 

of DO.
vand

142 4 Balance Principles

and the balance of angular momentum (or balance of moment of momentum or balance of rotational momentum) as

.

D f

D

f

r x p0 VdV = M(t)

,

(4.39)

J(t) = Dt.

r x pvdv = Dt.

 

 

 

n

no

 

 

 

which are given in both the spatial and material descriptions.

In relations (4.38) and (4.39), F(t) and M(t) are vector-valued functions. They characterize respectively the resultant force and the resultant moment (or resultant torque), i.e. the moment of F about x0 The momentum balance principles are generalizations of Newton's first and second principle of motion to the context of continuum mechanics, as introduced by Cauchy and Euler. The contributions to linear momentum L and angular momentum J of a body are due to external sources, i.e. F and M, respectively. If the external sources vanish linear and angular momentum of the body

are said to be conserved.

 

 

 

By virtue of relation (4.34) we may rewrite the balance principles as

 

L(t) =

./ pVdv = ./PoVdll = F(t)

(4.40)

 

n

flo

 

j(t) =

/

r x pVdv = ./ r x µ 0 Vdlf = M(t)

(4.41)

 

n

flu

 

Here, we have used the relation r x v = r x v, since r = x= v according to (4.37) 1 and (2.28) 1, and consequently r x v = v x v = o. The spatial and material acceleration fields are characterized by V(compare with Section 2.3 ). The so-called inertia forces per unit current and reference volume are denoted by pv and p0 V, respectively.

In the following we define the structure of forces acting on a continuum body. Consider a boundary surface an of an arbitrary region n which is subjected to the

Cauchy traction vector t = t( x, t, n)

(force measured per unit current surface area

of BO), as introduced in Section 3.1.

The unit vector n is the outward normal to an

infinitesimal surface element ds Furthermore, let b == b{x, t) denote a spatial

vector field called the body force. It is defined per unit current volume of region 0 acting on a particle, as illustrated in Figure 4.2. Note that the symbol b should not be confused with the strain tensor introduced in eq. (2.77).

A body force is, for example, self-weight or gravity loading per unit volume, i.e. b = pg with the spatial mass density p and the (constant) gravitational acceleration

g.

Hence, the resultant force F and the resultant moment M (about a point x0 ) on the

body in the current configuration have the additive fonns

 

F(t) = / tds + ./ bdv ,

(4.42)

an n

4.3 Momentum Balance Principles

143

b

t

..1\•1.1, X•1

1)

time t

Figure 4.2 Structure of forces acting on the current configuration.

M(t) = .!r x tds + .!r x bdv .

(4.43)

 

 

{}fl

fl

 

Finally, by virtue of eqs. (4.38) and (4.39) the global forms of balance of linear momentum and balance of angular momentum may be given in the spatial description as

D ;·

tds +

bclv ,

(4.44)

Dt .

pvdv =

.

 

 

n

 

;m

 

fl

 

 

it .!r x pv<lv =

.!r x tels + .!r x bdv .

(4.45)

n

 

an

 

 

n

 

These equations are fundamental in continuum mechanics.

For the balance of angular momentum (4.45) we have assumed the restriction that distributed resultant couples are neglected. If we consider resultant couples throughout a body in motion, then the balance of angular momentum (4.45) reads as

D,

(4.46)

(r x pv + p)dv =

(r x t + m)ds +

(r x b + c)du .

 

t.

.

.

 

 

n

an

n

 

Here, m is the distributed assigned coupled traction vector per unit current area acting on the boundary surface an while c is the distributed assigned body couple (or also called body torque) per unit volume acting within the volume of region n. The spin angular momentum (or intrinsic angular momentum) per unit current volume is

144 4 Balance Principles

denoted by p. A continuum without distributed resultant couples is called .non-polar. If any. couple acts on parts of the continuum we say that the continuum is polar. Po- lar continua are not considered in this text. For a detailed study of .polar continuum mechanics se·e, for example, TRUESDELL and TOUPIN [1960] or MALVERN [1969].

In order to express the ·momentum balance principles in terms of materia·1 coor-

dinates we introduce the {pseudo) ·body force -called the reference body force B

=

B(X, t). It acts on the region n and is, in contrast to the body force h~ referred

to

the reference .position X and measures force per unit reference volume. With volume change dv = JdF and motion x = x(X, ·t) we find the transformation of the body force terms of eqs. (4.44) and (4.45) in the form

/

b(x, t)dv = /b(x_(X, t}, t)J(X, t)dl' = / B(X, t)dF

(4.47)

n

no

no

 

or in the loca] form as

 

 

 

B(X~ t) = J(X? t)b(x, t)

or

(4.48)

Using the first P.iola-Kirchhoff traction vector T = T(X, t, N) introduced in (3.1), relations (4.38), (4.39), (4.48) and d-v = .JdV.~ we conclude from (4.44) and (4.45) that

gt.!poVd'V =

.!TdS + .!BdV ,

(4.49)

nu

ano

no

 

gr x p0VdV = fr x TdS + ;· r x BdV ,

(4.5~_)

t .

.

.

 

no

ano

no

 

which are the global forms of balance of linear momentum and balance of angular momentum~ respective·ly, in the material description.

Equation of motion in s.patia:J and material descript.ion. A necessary and suffi.:.. cient condition that the momentum balance principles (4.44) and (4.45) are satisfied is the existence of a spatial tensor field .u so that t(.x, t, n) = u(x, t)n (see eq. (3.3)i) .

.By computing the integral fonn of Cauchy's stress theore.m (3.3)i and by using_-:·; divergence theorem (1.294), which converts the surfac~ integral into a volume integral,-..-.} we find that ···

/t(x, t, n)ds =

/ u(x, t)nds =

/ divu(x, t)dv ,

(4.51)

an

an

n

.. ·.

where u :is the sym-metric Cauchy stress tensor.

By substituting this

result into the·;:)

balance of linear momentum (4.44), and using (4..38}, (4.40), we may show that.~/.:;:

satisfies the Cauchy's .first equation of motion

·'/)

 

:. -.:_ ·.:·/{

/ (divu + b - pV)dv = o

(4.52)/

n

...-::-:-

4.3 :Momentum Balance Principles

145

here presented in the global form. This relation is supposed to hold for any volume v. Hence, we may deduce Cauchy"'s first equation of motion in the local fonn, i.e.

divu + b = pv or (4.53)

for each point x of v and for all times t.

The differential equation of motion is here presented with respect to the current configuration. Note that the material time derivative of the spatial velocity field v is, according to (2.26), given as v= av/at+ (gra<lv)v or, in terms of the spin tensor ·w, according to (2.151), given.as v=av/at+ (1/.2)grad(v2 ) + 2wv.

Generally, re]ation (4.53) is nonlinear in the displace·ment field u. The nonlinear-

. ities are implicitly present due to ge01netric sources, i.e. the kinematics of ·motion of the body, and material sources, i.e. the material itself - the Cauchy stress u may, in

. generat depend on u.

If the ac·celeration is assumed to be zero for all x E n (note that a constant velocity :... field is not excluded)., eq. (4.53) becomes

divu + b = o

or

(4.54)

?->N.hich is referred to as Cauchy's equation of equilibrium in elastostatics. A spatial

·/·s.tress field satisfying divu = o is called self-equilibrated.

:·.·...

rlt:XAMPLE 4.3 Show that Cauchy's first equation of motion may also be written in /:?rile important equivalent form

8(pv)

.

(4.55)

-- ·=div(u -

pv ® v) + b .

at

 

 

.~·;·:·;.":·::..:··.:·: ...

·.:

:

ii;~6Jution. In order to reformulate the term pV on the right-hand side of eq. (4.53) we

:::::_;;W6piy (2.26), the product rule and the continuity mass equation in the form of (4.1.4) to

:Jr:hbtain

.

Dv

EJ(pv)

Dp

 

 

pv == p - + p(gradv)v =

{)

· -

~v + (graclv)(pv)

 

8t

·t

 

ut

-

·

=

a~v) + vdiv(pv) + (gradv)(pv) .

 

(4.56)

 

t

 

 

 

 

 

:::with (l .290) we find finally the identity

 

 

 

 

 

 

pV = O~v) + div(pv ®

v)

 

(4.57)

 

·t

 

 

 

 

 

.::::'(Which also comes from eq. (4.21)2 with u rep1aced by v). Substituting (4.57) into

!J::::~=~,_:.·~·3) gives the desired result. •

146 4 Balance Principfos

For solid bodies, it is sometimes more convenient to work with the material description. Hence, we rearrange the equations of motion (4.52) and {4.53) in .terms of quantities wh.ich are refeITed to the .reference configuration. To begin with, we intro- duce the P.iola ·identity, which .is

 

............~ __, .....,,,.,,,.__,,,., ...,.,,.,

 

 

 

 

.........

 

 

 

 

. . .. . .. . ... . ·:" ..

 

D(.!~4~) = 0 .

 

 

_piy(!~~-~~)·· ... · o~

or

(4.58)

 

 

 

D~\:A

 

 

.~-~·· ... .. . . .

 

 

 

Pmol

To prove the important ide.ntity (4.58) we pick any region n0

of a contin-

uum body with boundary surface Bnn and apply the divergence theorem twice. With (1.298), Nanson's formula (2.54) and ( 1.294), we obt~in simply that

'

1

1

\.

 

./ Div(JF-'')dV= . JF-''NdS

. ; nd.s

 

no

 

imo

 

an

 

 

 

= /1nds =.!~dv =o . II

(4.59)

 

 

im

n o

 

Now with this identity, Piola transformation (3.8), the product rule and the symme- try of u we may take the -divergence of the first Piola-Kirchhoff stress tensor P with respect .to the material coordinates, i.e.

,__ Div?. ··. Div( J o-F~_'r)

= .Div['!{,l_F.'..~~r)] .,,

 

 

-·,··-····= .l(Piv«:T)F-T +CT bfv(JFjT) =

.J(D•vO')F-T .

(4.60)

.

(";<-·,,,,... ... .

'

. 'V" ...·· _,,

--- ·..,,..'~------

 

 

 

 

 

•. ··: '•·,,. .,. ·:·· -C'''·'"'~·-...--~.-~-,,.....-

 

 

 

 

0

 

 

By recalling relation (~.49) we obt&;l.ill the·lransformation

 

·.........

...:·'"

 

 

 

 

 

.:...~ ·.:·=

 

 

 

 

 

;:

 

 

 

 

 

 

or

 

 

(4.6.1)

Combining this resu]t and e-qs. (4.47)2 and (4.40) with Cauchy's first equation-nf motion (4.52) we obtain, after a change of variables and use of dv = Jell/,

/(Di\•P + B - p0'V)dF= o .

(4.62)

no

 

It is the global form of the equation of motion in the reference configuration. Since the volume v (and therefore l/') is arbitrary, we obtain the associated local form, i.e.

DivP + B == pnV

or

o~i.4

•..

(4.63)

:v .

+ Ba = Po l ....n

 

 

a..··\A

 

 

in which the independent variables are (X.~ t) ..

The equilibrium counterpart of (4.63) is given simply by setting V~ {f..·~), equal to zero.

4.3 Momentum Balance Principles

147

Symmetry of the Cauchy stress tensor. The Cauchy stress tensor u is symmetric,

as can be seen from the global form of balance of angular momentum (4.45) as follows. Knowing Cauchy's stress theorem (3.3) 1 and the divergence theorem, as given in.( 1.300), we are able to convert the first term on the right-hand .side of eq. (4.45) to a volume .integral according to

Ir xtels= Ir xo-nds = /(r xdiva-+ e : uT)dv ,

.(4.64)

iJn

an

n

 

where E denotes the third-order permutation tensor introduced in eq.. ( 1.143). With (4.:64) and relations (4..39), (4.41) we are now ab.le to rewrite (4.45) as

/

r X (pV - b - divo-)d'V = / £: uTclu ,

(4.65)

n

n

 

Using the equation of motion (4.53) and the fact that the current volume v is arbitrary~ we conclude that

 

'(\

= 0

or

 

(4~66)

 

e: U ..

 

which holds at each point x of the region and for all times 't.

The double contraction

.e:UT gives a vector with components CalJr~ac1" which must be zero. We see that

 

.-

-..~) = ·o '

 

a~n -

0"1.2 = 0 .

(4.67)

.a3·> -

·<J"')'J

 

 

 

;· This relation is satisfied, {f and 011/y if the Cauchy stress tensor u is symmetric, i.e.

or a alJ = a,J.(l (4.68)

.............

The crucial result (4.68) is a local consequence of the balance of angular momen- ·.· tum (4.45), often referred to as Cauchy's second equation of.motion. From eqs. (3.62)

and (3.65) 1 we deduce that the Kirchhoff stress tensor T and the second Piola-Kirchhoff stress tensors are also symmetric. However, from eq. {3.67) we find that the .first Piola-

. Kirchhoff stress tensor P is, in general, not symmetric as indicated in (3.10).

.. . . Note that for a polar continuum (resultant couples are not zero) the symmetry prop-

..;> ~rty does not hold any longer {u ¥- u'I)and therefore eq. (4.68) may also be viewed ·:.:.· ?s'a constitutive equation (compare with Exercise 5 on p.. 152).

:..... ._:_.:·_·.

<System of forces and .How. The Cauchy traction vector t = t(x, t, n) and the body :;J~rce b = b(x, t) acting on an and n(see eq. (4.42)) during a motion x consistent with i'/:themomentum balance principles form .a so..called system of forces. To each system

:\:of forces (t, b) corresponds exactly one sym:metric stress tensor field u = q-(x, t)

'./.{.satisfying the equation of .motion (4.53), i.e. -divu + b = pv, and Cauchy's stress

/\~heorem (3.J)i, i.e. t = an.

(u, x)
(t, b)

148 4 Balance Principles

In other words, given the Cauchy stress tensor u = u(x, t) (that is defined to be a smooth function of x) and a motion x = x(X, t), then the system of forces may be uniquely determined. The Cauchy traction vector t follows from Cauchy's stress theorem (3.3)i, while the body force bis obtained from the equation of motion (4.53). The spatial mass -density p therein results from the continuity mass equation. The pair

defines a so-called dynamical process, or just a process, for convenience.

EXAMPLE 4.4 A dynamical process (u, x) is given by the Cauchy stress tensor u

in the form of the matrix

(4.69)

where a and f3

? 10)) ·

eq. ( -·· . , 1.e.

are scalar constants., and by a motion according to Example 2.2 (see

:z; 1

= e ..-·\. 1 - e

....\.:h x2

= e ....-\.

1 + e

.....-\ 2 , .rz:a

= ..i\. 3

1.or

t

> ·..

 

·t

-t ,_.:""

f.

 

-t ,.-

i/·

.i:

0

Find the system of forces (in matrix notation) so that Cauchy's first equation of motion (4.53) and continuity mass equation in the form of eq. (4.10) are satisfied. The Cauchy traction vector t is assumed to act at a point x of a plane tan_gential to a sphere, given by equation <I> = ~z:i + :z;~ + :r:5.

Solution. In order to determine the components of the traction vector t from

Cauchy's stress theorem we must find the unit vector .n normal to the surface 4>, which is n = grad<!>/lgrad<I>I = x/lxl (see Figure 1.9).

Hence, the com_ponents oft take on the values

(4.70_)

In order to determine the components of the body force vector ht. we rewrite Cauchy's equation of motion so that (b] = p(v] - [divu], which .requires the computation

of p, [v] and [divu].

 

p =

The spatial mass density p follows from the inverse of relation (4 ..10),

i.e.

,J- 1p0 , where the volume ratio J is for the given motion (2.10) equal to 2.

The com-

ponents of the spatial acceleration .field are a.·1 = ·u-1 = :1:11 a 2 = 'lJ2 ::;::: :r:~h a:-J

= 'lJ3

= 0

(compare with Example 2.2, eq. (2.14)) and the divergence of the Cauchy stress tensor gives a vector with components (2:1: 1 + o:x~, 2x2 , 0).

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