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150

CHAPTER 7

Figure 7.13. Thermodynamicpath in the pressure-specific volume plane.

(7.7.1)

Now since w on the upper branch of curve ABC, where dp < 0, is > w on the lower branch, where dp > 0, w dp < 0. It follows immediately then that q > –

Now, in strict point of fact, the enthalpy difference – is different from the right-hand side of Eq. (7.5.1). For the temperature at point C is less than Tcs because

in the isentropic expansion BC, the

temperature falls. The enthalpy

difference

– can be calculated as follows:

 

 

 

and

(7.7.2)

Now since

Then

 

Internally Cooled Superconductors

 

 

 

151

 

 

 

 

 

 

 

 

 

 

 

(7.7.3)

Then, subtracting the second of Eqs. (7.7.2) from the first, we find

 

 

 

 

 

 

 

 

= T(∂s/p)T(–pB)= bTwpB

(7.7.4)

by making use of the Maxwell

relation (∂s/p)T = – (w/T)p = –bw. Thus the

error in

using Eq. (7.5.1)

for

the

stability margin is

 

bTpB(AHe /Aco).

 

 

pB , then for the conditions of the experiment of Lue

 

If we use pmax in place of

et al. quoted in Section 7.4, pB

= 0.214 MPa, b = 0.0843 K-1, Tb = 4.2 K, and

A

/A

co

= 0.786. Then bTp

B

(A

He

/A

co

) = 5.96 x 104 J /m3 = 59.6 mJ/cm3. Typically,

He

 

 

 

 

 

 

 

stability margins are several hundred mJ/cm3 (cf. Fig. 7.7), so the fractional error incurred by using Tcs as the upper limit in the integral in Eq. (7.5.1) is not large.

The thermodynamic arguments given so far are based on the assumption that a single pair of thermodynamic variables describes the entire normal zone, and from the work of Sections 7.3 and 7.4, we know this is not so. At any single instant, the thermodynamic states of different fluid elements may differ from one another.

In view of all these caveats, it would appear that the estimate of Eq. (7.5.1) has no rigorous interpretation. Nonetheless, it is useful as a figure of merit, for when it is high the upper stability margin is high, and when it is low, the upper stability margin is low. In addition, it is easy to calculate, a property that has great utility in survey calculations.

7.8. THE LOWER STABILITY MARGIN

As mentioned in Section 7.6, the lower stability margin is characterized by the condition that the duration of the normalizing pulse just equals the time t to takeoff. If we ignore the Joule power compared to the heat flux qJ = DHAco /Pt and substitute the last expression into Eq. (7.6.1), we obtain

DH = 4Ct1/2/Dw

(7.8.1)

where Dw is the wire (strand) diameter. The right-hand side of Eq. (7.8.1) should be an upper bound to DH because of the neglect of Joule power generation.

Lue and Miller (1981, “Heated length”) measured the lower stability margin of a triplet of 1-mm strands soldered around a central heater wire. The ambient helium pressure was 0.5 MPa and the ambient temperature was 4.2 K, for which conditions, I have calculated that C = 26 mW cm–2 s1/2 (Dresner, 1984, “Superconductor stability”). For pulse times of 10, 50, and 100 ms, we calculate from Eq. (7.8.1) that DH = 87, 194, and 274 mJ/cm3, respectively. (The results from Eq. (7.8.1) have been reduced by a factor of 5/6 to account for the fact that in a soldered

152

CHAPTER 7

triplet only 5/6 of the surface is wetted.) The corresponding experimental results are 60, 100, and 140 mJ/cm3 and are slightly lower than the upper bound calculated from Eq. (7.8.1). In Dresner (1984, “Superconductor stability”), an estimate is presented of the Joule power required to reduce the calculated DH to the measured value. It is given as 36%, 25%, and 18%, respectively, of the fully normal heat flux, indicating that the conductor appears only to have been driven into the current sharing range by the initial pulse.

Notes to Chapter 7

1The idea of increasing the surface by subdividing a fixed volume is ancient. To my knowledge, the first suggestion in this direction regarding superconductors came from Chester (1987), who wrote, “Clearly, excellent thermal contact is desirable between the superconductor andthe thermal ballast . . . this is achieved by subdivision of the superconductor to present greater interfacial area.” The present era of development of cable-in-conduit conductors began in 1975 with a reminder from Hoenig, Iwasa, and Montgomery(IEEE Transactions) of the advantages of subdividing the superconductor by cabling. A review of this earlier work can be found in Dresner, 1980, “Stability.”

2If the reader has any doubts about the correctness of leaving the frictional force out of the energy equation, the following observation should settle them. The power dissipated by the frictional force per unit volume is –rFv. If this term were included on the right-hand side of Eq. (7.2.3), the term Fv would not appear on the right-hand side of Eq. (7.2.7). Then the dissipation of kinetic energy into heat would produce no entropy, an obvious contradiction.

3Riemann’s method was invented to deal with hyperbolic partial differential equations, the classical example of which are the equations of compressible flow. The interested reader can find detailed discussions of the method in the books of Courant and Hilbert (1953), or Courant and Friedrichs (1948).

4In the simplest problems of gas dynamics the Riemann invariants do not change along the characteristics and this accounts for their names. We continue to use this name here for convenience even

though the presence of a heat source causes the “invariants” to change along the characteristics.

5Strong heat transfer promoted by transient heat conduction occurs early in supercritical helium as well as in boiling helium. Whereas in boiling heat transfer the transient phase comes to a close (takeoff) when the surface is blanketed by vapor, in supercritical heat transfer the transient phase comes to a close when the temperature of the surface reaches the so-called pseudo-critical line where the density of the helium drops sharply. Takeoff in supercriticalhelium is thus caused by the blanketing of the heat transfer surface by low-density helium, a process sometimes called pseudo-boiling. The time to takeoff in supercritical helium varies as the reciprocal square of the heat flux just as in boiling helium and the two times are not terribly different in magnitude for the same heat flux.

8

Hydrodynamic Phenomena

8.1. NEGLECT OF FLUID INERTIA

When a potted magnet quenches, the main protection issue is the spreading of the normal zone and the final hot-spot temperature. When a magnet cooled by a boiling cryogen quenches, another protection issue arises: the pressure rise in the dewar caused by the vaporization of the boiling coolant. The resolution of this issue is to provide a suitably large pressure-relief tube and does not usually influence the design of the conductor. When an internally cooled conductor quenches, especially a cable-in-conduit conductor, almost all of the hydraulic resistance to the expulsion of the helium comes from the conductor itself. (Consider, for example, the Westinghouse conductor (Fig. 7.1), for which the hydraulic diameter D is 0.4 mm and the hydraulic path length L is 120 m; it has an L/D ratio of 3 x 105!) For such conductors, the issues of protection cannot be divorced from the design of the conductor, and so we consider them here. These issues, all interconnected, are the rise in internal pressure, the thermal expulsion of helium from the ends of the conductor, the propagation of normal zones, and the possibility of hydrodynamic quench detection.

The rise in internal pressure in a quenching cable-in-conduit conductor such as the Westinghouse conductor is a relatively slow process compared with the process of recovery, the former lasting for seconds, the latter only for milliseconds. In seconds, the disturbance created by the expanding helium in the normal zone spreads over many diameters. As already noted in Section 7.2, when a disturbance has spread over many tube diameters, the chief restraining force on the fluid is friction, and the inertia of the fluid may be neglected. Therefore, in treating the late-stage hydrodynamic problems of protection, we shall set to zero the left-hand side of Eq. (7.2.2), which is the inertial term. Then Eq. (7.2.2) simply becomes

p/ z = rF

(8.1.1)

153

154

 

CHAPTER 8

Using Eq. (8.1.1) for the derivative p/z, Eq. (7.2.9) becomes

 

 

p/t + rc2(∂v/ z) = (brc2/cp )[q + Fv(1+ cp /bc

2)]

(8.12)

Consulting the tables of Arp and McCarty (1989), we find

that

the quantity

cp /bc2 is always close to 1.

 

 

8.2. MAXIMUM QUENCH PRESSURE

To bound the internal pressure that the conductor might suffer, let us assume an entire hydraulic path has gone normal all at once. We presume the ends of the hydraulic path intrude into large plenums held at constant pressure, so that there is no pressure rise at the ends of the hydraulic path. According to Eq. (8.1.1), the pressure rise is largest at the central element, where it equals

po = (2f/D) rv 2dz

(8.2.1)

0

 

where = L/2. We now assume that the velocity has a linear profile, being zero at the center and having a maximum vm at the open ends. Then Eq. (8.2.1) becomes

po = (2f/D )rvm2

(8.2.2)

For the central fluid element, for which v = 0, Eq. (8.1.2) becomes

 

po/ t + rc2(vm / ) = brc2q/cp

(8.2.3)

or using Eq. (8.2.2) to eliminate vm in favor of po,

 

po/t+ (ρc2/ )(3poD/2ρ ƒ)1/2 =βρc2q/cp

(8.2.4)

When po achieves its maximum pm, po/t = 0, and then it follows from Eq. (8.2.4) that

pm = (2f /3)(b2r/cp2)(q2 /D) = (2f /3)(b2/rc2p)(Q2 /D)

(8.2.5)

where Q = rq is the Joule power density in the helium.

In Miller et al. (1980, “Pressure”), it is shown that the thermodynamic group b2/rc2p depends only weakly on density and can be approximated roughly by 0.45p–1.8 in SI units, where p denotes absolute pressure, rather than pressure rise. Substituting this correlation into Eq. (8.2.5), we obtain the approximate formula

pm= 0.65f 0.36(Q /D)0.36(1– pa/pm) –0.36 (SI units)

(8.2.6)

Hydrodynamic Phenomena

155

where pm is the maximum absolute pressure and pa is the ambient pressure.

 

The last term varies slowly with the ratio pm /pa when this ratio is

large

compared to 1. For 3 < pm/pa < 20, the last term in Eq. (8.2.6) varies between 1.16 and 1.02; here we use the mean value of 1.09. Measurements of the friction factors of typical cable-in-conduit conductors (Lue et al., 1979; Daugherty and Sciver, 1991) indicate that ƒ~ 0.02 and is determined largely by the roughness of the cable. With these simplifications, Eq. (8.2.6) becomes

pm = 0.17(Q /D)0.36 (SI units)

(8.2.7)

At different times in the past, the constant in Eq. (8.2.7) has been given different values, depending on the state of knowledge about the friction factor f at the time. In the original work in which the results (8.2.6) and (8.2.7) were derived (Miller et al., 1980, “Pressure”), the constant was 0.10. In a somewhat later work (Lue et al., 1982), it was raised to 0.14, and now we prefer the value 0.17. Fig. 8.1 shows experimental points collected by Lue et al. (1982) compared with Eq. (8.2.7) using values of the constant of 0.10 and 0.14. The agreement is good, and Eq. (8.2.7) can be used confidently for design purposes.

The formula (8.2.7) has occasionally been misapplied by using it when the ratio pm/pa is close to 1. A single example will suffice to show what kind of errors are possible. Suppose ƒ= 0.02, Q /D = 1019 W2 m–4, and pa = 1 MPa. Eq. (8.2.7) gives pm = 1.176 MPa, whereas Eq. (8.2.6) gives pm = 1.578 MPa. The calculated

Figure 8. 1. Experimental data from Lue et al. (1982) compared with Eq. (8.2.7) using values of the constant of 0.10 and 0.14. (Redrawn from an original appearing in the Proceedings of the Ninth Cryogenic Engineering Conference, K. Yasukochi (ed.), Kobe, Japan, May 11–14, 1982, pp. 814–818, by permission of the publishers, Butterworth-Heinemann Ltd. ©)

156

CHAPTER 8

pressure rises differ by a factor of 3.3! If, on the other hand, Q

/D = 1022 W2 m–4,

Eq. (8.2.7) gives pm = 14.14 MPa and Eq. (8.2.6) gives pm = 13.59 MPa. The absolute pressures differ by only 4.0% and the pressure rises by only 4.4%.

8.3. THERMAL EXPULSION

Thermal expulsion of the helium from the open ends of a fully normal hydraulic path has also been studied experimentally (Lue et al., 1982), but the emphasis was on times somewhat shorter than that required for a linear velocity profile to develop (cf. Fig. 8.2). When the elapsed time is short, the pressure relief waves penetrating inward from each open end have not yet reached the center. Until they do, the expanding helium near each end behaves as though the hydraulic half-length were infinite. This means we must solve the partial differential Eqs. (8.1.1) and (8.1.2) subject to the boundary and initial conditions

p(0,t) = 0, v(∞,t) = 0, p(z,0) = 0, v(z,0) = 0

(8.3.1)

Here z = 0 is taken to be the open end of the conductor with positive z pointing inwards, and t = 0 is taken to be the instant at which the conductor becomes normal.

Figure 8.2. The thermal expulsion velocity from the open ends of a fully nomal test conductor as a function of time (Lue and Miller, 1982). (Redrawn from an original appearing in the Proceedingsof the Ninth Cryogenic Engineering Conference, K. Yasukochi (ed.), Kobe, Japan, May 11–14, 1982, pp. 814–818, by permission of the publishers, Butterworth-Heinemann Ltd. ©)

Hydrodynamic Phenomena

157

Before we make a direct attack on this problem, it behooves us to inquire if Eqs. (8.1.1) and (8.1.2) and the conditions (8.3.1) are invariant to stretching groups similar to that used in Section 6.2. Such a group is

= lz

= l–1/2v

0 < l < ∞

(8.3.2)

= l3/2t

= l–3/2q

with the other quantities(p, b, r, cp, c) being unchanged. For a fixed initial thermodynamic state, the expulsion velocity v(0,t) can only depend on q and t, i.e., v(0,t) = (q,t). This relation must be invariant to the transformations (8.3.1), i.e., (0,) = (, ) or

 

(8.3.3)

From Eq. (8.3.3) it follows that

 

(8.3.4)

where

is an as yet undetermined function of the single variable qt. This means

that if we plot the data in Fig. 8.2 using vt1/3 as ordinate and I2t ~ qt as abscissa, all the curves in Fig. 8.2 should, and do, collapse to a single curve (cf. Fig. 8.3).

The points in Fig. 8.3 correspond to points on the curves in Fig. 8.2 for which t < 1 s. For times t ~ 2 s or longer, the disturbance has reached the center of the conductor and the expanding helium no longer behaves as though the hydraulic half-length were infinite.

The function (qt) has been calculated by the method of similarity solutions (Dresner, 1981, “Thermal expulsion”), discussed in Appendix A. The result of this calculation is

vt1/3 = 0.952 (bc/cp)2/3(D/ƒ)1/3(qt )2/3

(8.3.5)

It is important to note here that this explicit form has been attained only at the cost of (1) assuming the thermodynamic properties of the helium remain constant, and

(2) ignoring frictional heating. In fact, r diminishes as helium is expelled from the conductor, so that on both counts Eq. (8.3.5) should underestimate v. As we can see from Fig. 8.3, it does so. The overall slope of the experimental points matches the theoretical slope of 2/3 fairly well, but the similarity solution is low by roughly a factor of 2.

158

CHAPTER 8

Figure 8.3. The data (for t < 1 s) of Fig. 8.2 plotted using the similarity variables vt1/3 and I2t. Shown, too, is the similarity Eq. (8.3.4). o) 500 A; ) 760 A; )1010 A; ) 1250 A. t = 0.2, 0.4, 0.6, and 1.0 s. (Redrawn from an original appearing in the Proceedings of the Ninth Cryogenic Engineering Conference, K. Yasukochi (ed.), Kobe, Japan, May 11–14,1982, pp. 814–818, by permission of the publishers, Butterworth-Heinemann Ltd. ©)

8.4.EXPULSION INTO AN UNHEATED PART OF THE CONDUCTOR

A problem closely related to thermal expulsion from an open end is thermal expulsion into an unheated part of the conductor. Imagine a very long tube, the left half of which is producing Joule heat while the right half is not. The heated helium on the left expands, intruding into the right half. We seek the velocity at which the hot helium crosses the boundary, i.e., the velocity of efflux of the helium from the left side into the right. With the same provisos as before, namely, constant thermodynamic properties and elapsed time short enough that there is no influence from the ends, we find the same result as that given in Eq. (8.3.4) except that the numerical constant 0.952 is replaced by 0.600. This result can be used to estimate the initial rate of expansion of a newly created normal zone, assuming, as we shall, that the normal zone is propagated by the expansion of the hot helium. For early times, then, the normal-superconducting front should move with a velocity proportional to the cube root of the elapsed time. Luongo et al. (1989, “Thermal hydraulic simulation”) report that Eq. (8.3.5) with the modified numerical coefficient agrees well with their numerical simulations.

8.5. SHORT INITIAL NORMAL ZONES

The problems discussed so far are all based on long initial zones: in Sections 8.2 and 8.3 an entire hydraulic path was assumed to go normal at the outset; in

Hydrodynamic Phenomena

159

Section 8.4, an infinite pipe was envisioned. We need to know in addition what happens when the initial normal zone is short. Now the problem is a two-region problem and is substantially more complicated than the problems just dealt with. Again we can simplify the problem by artificially breaking the problem into two one-region half-problems. The first half-problem concerns the flow induced in the cold helium by the expanding hot helium in the initial normal zone. To break the coupling we assume that we know how this hot-cold boundary moves. The expanding hot-cold boundary then acts like a piston that accelerates the cold helium, which, for the long times we are interested in (seconds, not milliseconds) is restrained by friction.

8.6. THE PISTON PROBLEM

If the disturbance created by this “piston” has not yet reached the open end of the hydraulic path, we can study the motion induced by the piston as though it were taking place in an infinite tube. Thus we must solve Eqs. (8.1.1) and (8.1.2) with the boundary and initial conditions

v(z,0) = p(z,0) = v(∞,t) = p(∞,t) = 0

(8.6.la)

v(Z,t) = dZ/dt

(8.6.1b)

where Z(t) is the location of the piston, assumed known. Indeed, in what follows we take Z(t) = Xtn, where X is a known constant of proportionality. Thus we take the displacement of the piston to be proportional to a power n of the elapsed time. Furthermore, in the cold helium q = 0. To make the calculation possible, we restrict ourselves to small velocities v, so that the frictional v3-term on the right-hand side of Eq. (8.1.2) can be neglected. (Later, we shall mention the conditions under which this neglect is permissible, i.e., the conditions under which the solution we shall obtain is self-consistent.) Finally, we treat the thermodynamic properties of the helium as constants independent of temperature and pressure.

If we introduce special units in which r = c = D/4f = 1 (respective dimensions: ML–3, LT–1, L), Eqs. (8.1.1) and (8.1.2) become

p/z = –v2/2

(8.6.2)

p/t + ∂v/z = 0

(8.6.3)

from which it follows by elimination of p that

 

v(∂v/∂t) = ∂2v/ z2

(8.6.4)