ТЭД - Лекция 3 2019

$

21

$

22

++ "

H

=

i icmlk 2 1

1

2

−ikr

H rm

= Hθm = 0

m

− i

sin θ e

ϕm

4π

kr

kr

.$

Em

= −

i

rotH m

ωε

r

Em = −

i

∂

(sin θ H

∂

(r H

0

ϕm ) − θ0

ϕm )

ωε r sin θ ∂

∂r

E

= r

E

E

+ θ

0

m

0

rm

θm

k = 2π / λ

k 2 = 2πω εµ / λ

i imcml

i imcml

Eθ =

µ

sin θ e

i (ωt −kr )

Hϕ

i (ωt −kr )

=

sin θ e

2λr

ε

2λr

! -/

,

= const

r=const

E

H

! +$ -0 ωt − kr = const

E0 , t0 , r0

Ψ0 = ωt0 − kr0 + π / 2

t1 = t0 + t

ω t0 = k r

v = r0v = r0

lim ( r /

t) = r0 (ω / k ) = r0 c

t →0

c =

1

=

c0

; c0

=

1

= 3

10

8

/ c

ε 0 µ

εµ

ε r µr

0

+, / ,

26

2πr << λ r >> l

Hϕm

=

i icmlk 2

1

1 2

−ikr

l << r << λ / 2π

m

− i

sin θ e

4π

kr

kr

icmlk 3

1 2

1 3

E

=

m

− i

cosθ e−ikr

rm

2πωε kr

kr

E

ii cml cosθ

ei (ωt −kr )

Eθ =

iimcml sin θ

e

i (ωt −kr )

=

m

4πωε r 3

2πωε r 3

r

=

imcml sin θ

i (ωt −kr )

Hϕ

e

4πr 2